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Title POTEMindd Author christopherdinardo Created Date 11/19/ PM. Re g i o n A l a rg e a re a t h a t h a s co mmo n f e a t u re s su ch a s l a n g u a g e , cu l t u re , a g ri cu l t u re , re l i g i o n O n p a g e # 5 G e o g r a p h y Ge ogra phy i s t he s t udy of t he e a rt h’s phys i c a l fe a t ure s a nd pe opl e ’s re l a t i ons hi p wi t h t he m O n p a g e # 5. 7 Words Pictures 1 l a b G A c a b 3 1 G 2 n a b F B a x 10 2 J 3 c a b A C t a from IRAQ KDL at Iraqi University You've reached the end of your free preview Want to read all 174 pages?.
D r a w n t h r o u g h a f i g u r e a nd e a c h s i d e o f l i ne i s a mi r r o r i ma g e d T r a ns f o r ma t i o ns Rotation every 90 ˚ , the x and y value switch Use negative coordinates depending on which quadrant the point is in Translation – move each point of a figure using the same rule. Mo n d a y, No ve mb e r 2 0 t h S t u d e n t s wi l l co n t i n u e wo rki n g o n t h i s p ro j e ct i n cl a ss e ve ry d a y u n t i l De ce mb e r 7 t h T h e y wi l l b e co mp l e t i n g t h e f o l l o wi n g Re a d i n g t h e i r a ssi g n e d se ct i o n s i n t h e i r wo rkb o o ks. 4 On last week’s homework, we showed that if G is an abelian group and H = {g ∈G g2 = e}, then H is a subgroup of GThis fact is only true of abelian groups Verify that H = {a ∈S 3 a2 = e}is not a subgroup of S 3 Answer We compute that the set H = {a ∈S 3 a2 = e}= {e,g,h,k}This can’t possibly be a subgroup of G, because it has 4 elements and G has 6 elements Specifically.
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