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 · Take (natural) logarithms of both sides ln(xmyn) = ln((x y)mn) Then using the properties of logarithms we can simplify ln(xm) ln(yn) = ln((x y)mn) ∴ mlnx nlny = (m n)ln(x y) Now we can differentiate implicitly m x n y y' = m n x y (1 y') ∴ m x n y y' = m n x y m n x y y' ∴ m n x y y' − n y y' = m x − m n x y. î z à ï $ ¶ 8 $ à. X n=0, s=0 n=n1 s=sn n < 10 x a Ý g Ý ° x print t ä u s print t ä u s * û 3 Ð > ø ûs start i i i = 100 stop i = 0 i = i 1 Ø ä ß Ø ä ß g÷ gø gù gú gû b d x ü à 8* Ä à î 8 × î s × g 8 Þ È ³ 7 ~ 3 î &* À Ý ° & î s × g 8 y ñ & î gû* d Ý ° b À w b ;.

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